An aqueous solution of 10.00 g of an enzyme has a volume of 1.00 L at 23°C. The solution's osmotic pressure at
An aqueous solution of 10.00 g of an enzyme has a volume of 1.00 L at 23°C. The solution's osmotic pressure at 23°C is found to be 0.801 torr. Calculate the molar mass of the enzyme.
__________g/mol
More Questions From This User See All
Answers & Comments
Verified answer
T = 23+273 =296 K
p = 0.801 / 760 = 0.00105
n = 0.00105 x 1 / 0.0821 x 296 = 0.0000443
10.00 g / 0.0000443 = 2.26 x 10^5 g/mol
o.p = cRT R IS CONSTANT SO O.P WILL DWEPEND UPON CONCENTRATION I THINK ANSWER IS 0.1 0 M C12H22 O11 BCZ CONC IS MORE MORE IS OP