10.)
An 11 Ω resistor and a 44.0 Ω resistor are
connected in parallel to a battery, and the
current in the 11 Ω resistor is found to be 1.97A.
Find the potential difference across the battery.
Answer in units of V
11.)
a circuit breaker turns off the circuit
when the current reaches a certain amount.
For this problem, just calculate the total current flowing out of the outlet when both appliances operate at the same time (they are in parallel).
Your toaster oven and coffeemaker each dissipate 1200 W of power. You have a 109 V line in your kitchen.
For what current must the circuit breaker
be rated for you to operate both of these
appliances at the same time?
Answer in units of A
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Answers & Comments
Verified answer
10) Current through resistor = I = 1.97 A
Resistance = R = 11Ω
P. D. across the resistor = P. D. across the battery = V = I * R = (1.97 A)*(11Ω ) = 21.67 V
11) Wattage of the Toaster Oven / Coffeemaker = W = 1200 W
Line Voltage = V = 109 V
Current through each appliance = I
W = V I
=> I = W / V = (1200 W) / (109 V) = 11.01 A
Total current flowing out of the outlet = 2*(11.01) A = 22.02 A
The Circuit breaker may be rated for 25 A
10]
P.D. = 11 * 1.97 = 21.67 V
11]
Current in each = 1200 / 109 = 11.009 A = 11 A (approx)
Total current = 11 * 2 = 22 A
Rating should be a little above 22 A