B)A weather balloon is inflated to a volume of 26.2 L at a pressure of 744 mmHg and a temperature of 27.9 ∘C. The balloon rises in the atmosphere to an altitude where the pressure is 370. mmHg and the temperature is -15.2 ∘C.
Assuming the balloon can freely expand, calculate the volume of the balloon at this altitude.
C)The tire is inflated (while cold) to a volume of 11.8 L and a gauge pressure of 36.0 psi (Note: The gauge pressure is the difference between the total pressure and atmospheric pressure. In this case, assume that atmospheric pressure is 14.7 psi.) at a temperature of 12.0 ∘C. While driving on a hot day, the tire warms to 65.0 ∘C and its volume expands to 12.2 L.
What is the total pressure (gauge pressure + atmospheric pressure) in the tire after warming on a hot day?
Answers & Comments
(1.50 mL) x (0.3 + 273.15) K / (92.1 + 273.15) K = 1.12 mL
B)
(26.2 L) x (744 mmHg / 370. mmHg) x (-15.2 + 273.15) K / (27.9 + 273.15) K = 45.1 L
C)
(36.0 psi + 14.7 psi) x (11.8 L / 12.2 L) x (65.0 + 273.15) K / (12.0 + 273.15) K = 58.2 psi total