A stone is thrown at 25 m/s at 50° above the horizontal.?
At what time(s) is its velocity at 30° to the horizontal? A brief explanation of which equations used and with which values of x, vi, v final, t, and a would greatly help.
More Questions From This User See All
Answers & Comments
Verified answer
Horizontal component of velocity is 25 cos 50 = 16.07 m/s
Vertical component of velocity = 25 sin 50 = 19.15 m/s
When the velocity is 30˚ to the horizontal V cos 30 is the horizontal component and
V sin 30 is the horizontal component.
V cos 30 = 16.07
V = 18.56 m/s
Vertical component = 9.28 m/s
time taken for speed to drop from 19.15 to 9.28 is
9.28 = 19.15 – 9.8 . t
t = 9.87 / 9.8 = 1.007 = 1.0 s
time to top of flight = 19.15 / 9.8 = 1.95 s
Time to gain 9.28 m/s = 9.28 / 9.8 = 0.947 s
Total time to the second 30˚ ( – ) to the horizontal = 1.95 + 0.947 = 2.90 s