Let HCO4 = HClO4
Let each value be a molarity.
Assume 1.00 L of each is mixed.
0.054 mol + 0.026 mol = 0.080 mol
0.080 mol divided by 2.00 L = 0.040 M
Both acids are strong acids, so [H+] = 0.040 M
pH = -log 0.040 = 1.40
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Let HCO4 = HClO4
Let each value be a molarity.
Assume 1.00 L of each is mixed.
0.054 mol + 0.026 mol = 0.080 mol
0.080 mol divided by 2.00 L = 0.040 M
Both acids are strong acids, so [H+] = 0.040 M
pH = -log 0.040 = 1.40