A satellites are placed in a circular orbit that is 4.61 × 108 m above the surface of the earth. What is the m?
A satellites are placed in a circular orbit that is 4.61 × 108 m above the surface of the earth. What is the magnitude of the acceleration due to gravity at this distance?
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Verified answer
The Force due to Gravity is Found using This Equation
g=(GM)/r^2)
where g is the force of gravity
G is a gravitational Constant=6.67x10^-11
and r is the distance from the centre of the earth.
M is the mass of the earth, but because of certain circumstances im not going to describe, it is not needed here.
The earth has a radius of 6378100m
the satellites are 4.61x10^8m above the earth, so add that to the radius to find the distance from the centre of the earth.
which gives you 467378100m
so r=467378100
G=6.67*10-11
So G/r= 1.42711008x10-19
Which is perfectly reasonable for a satelitte of that distance away.