A sample of argon gas occupies a certain volume at 11°C.?
At what temperature would the volume of the gas be three times as big? Assume the pressure remains constant.
A. 33.3 C
B. 852 C
C. 94.7 C
D 109 C
E. 579 C
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Verified answer
Hi Vivian,
P x V = n x R x T
V / T = n x R / T
V / T = constante
. . . then :
V1 / T1 = V2 / T2
V2 = 2 x V1
T2 = V2 x T1 / V1
T2 = 3 x V1 x (273,15 + 11) / V1
T2 = 852,3 °K . . . . . . . . . . . . . . . . . . T2 = 579 °C
bear in mind, from PV=nRT P1V1/n1T1 = P2V2/n2T2 considering the fact that no longer something is suggested approximately rigidity and moles, they are going to be assumed to be consistent earlier and after replace subsequently: V1/T1 = V2/T2. additionally you're able to alter your temperature into Kelvin. (25 C = 298K ; 50C = 323K) Now plug each and every thing in: 0.ninety 5/298 = V2/323 V2 = 323*0.ninety 5/298 V2 = a million.0297 L