A Roman catapult fires a boulder with a launch speed of 30 m/s at an angle of 27° with the ground. What are th?
A Roman catapult fires a boulder with a launch speed of 30 m/s at an angle of 27° with the ground. What are the projectile's initial horizontal and vertical speeds?
__ m/s (horizontal speed)
__ m/s (vertical speed)
More Questions From This User See All
Answers & Comments
Verified answer
The horizontal speed is the initial velocity times the cosine of the launch angle, or 30 m/s times cos(27°)
The vertical speed is the initial velocity times the sine of the launch angle, or 30 m/s times sin(27°)
So, the initial horizontal speed is 30 * cos(27°) = 26.7 m/s and the vertical speed is 30 * sin(27°) = 13.6 m/s
You have two components of the initial velocity, Vx and Vy, for horizontal and vertical.
The horizontal component is the initial velocity, V, times cosX, which would be 30cos(27) = 26.73 m/s
The vertical component is the initial velocity, V, times sinX, which would be 30sin(27) = 13.62 m/s
Vh = 30*cos27°
Vv = 30*sin27°