increased by 3.9 x 10^-6 m^2, what is the final temp of the plate?
∆L/L = α∆T, α is linear thermal expansion coef
∆A/A = 2α∆T
∆V/V = 3α∆T
linear thermal expansion coef Al 23.1e-6 /K
∆A = A2α∆T
3.9e-6 = 0.51(23.1e-6)(∆T)
∆T = 0.33ºC
T = 25.33ºC
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Verified answer
∆L/L = α∆T, α is linear thermal expansion coef
∆A/A = 2α∆T
∆V/V = 3α∆T
linear thermal expansion coef Al 23.1e-6 /K
∆A = A2α∆T
3.9e-6 = 0.51(23.1e-6)(∆T)
∆T = 0.33ºC
T = 25.33ºC
.