Package 1: One - 10 x 14 Ten - 8 x 10's Cost: $239.50
Package 2: One - 10 x 14 Five - 8 x 10's Cost: $134.50
If we let x be the cost of a 10X14 and y be the cost of an 8X10 we get the following two equations:
x+10y=239.50
x+5y=134.50
We can rearrange the second equation and get:
x= 134.50 - 5y
Substitute and get:
134.50 - 5y +10y=239.50
rearrange for y
y= (239.5-134.50)/5
y=21
assuming the pictures cost the same regardless of package.
5 8x10 and 1 10x14 = 134.50
but 5 more 8x10 increases the cost to 239.50, the difference is 105.00 for 5 8x10, so an 8x10 would be $105/5 or 21$
One 8x10 is $21 and one 10x14 is 134.50-105 or $29.50
To prove:
then 5x21=105+29.50 for the 10x14 or 134.50 for package 2
10 times 21=210 + 29.50= 239.50 for package 1
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Verified answer
If we let x be the cost of a 10X14 and y be the cost of an 8X10 we get the following two equations:
x+10y=239.50
x+5y=134.50
We can rearrange the second equation and get:
x= 134.50 - 5y
Substitute and get:
134.50 - 5y +10y=239.50
rearrange for y
y= (239.5-134.50)/5
y=21
assuming the pictures cost the same regardless of package.
5 8x10 and 1 10x14 = 134.50
but 5 more 8x10 increases the cost to 239.50, the difference is 105.00 for 5 8x10, so an 8x10 would be $105/5 or 21$
One 8x10 is $21 and one 10x14 is 134.50-105 or $29.50
To prove:
then 5x21=105+29.50 for the 10x14 or 134.50 for package 2
10 times 21=210 + 29.50= 239.50 for package 1