A person notices a mild shock if the current along a path through the thumb and index finger exceeds 78 µA.?
Compare the maximum possible voltage without shock across the thumb and index finger with a dry-skin resistance of 4.0 105 and a wet-skin resistance of 2500 . wet skin? dry skin?
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I'm assuming the formula you would use for this is V=IR, which is Voltage = Current*Resistance.
So for the dry skin, plug in the values you know to give you, V = (78 µA)*(4.0105) = 0.000312819 = 3.12819e-4 . (Don't forget to convert the microAmps to Amps.)
For wet skin do the same thing, only with the wet skin resistance. V = IR = (78 µA)*(2500) = 0.195 . (Again don't forget to conver the micro.)
This means that wet skin has a higher maximum possible voltage than dry skin.
Electric Shock Notice
Vw = i*Ω = 78E-6*2500 = .195 V
Vd = 78E-6*4E5 = 31.2 V