Verified answer

i have this on online HW, and i've checked for the correct answer. both previous answers are on the right track, but are off a little bit or else are not expressed clearly. the equation needed is:

[delta x]/[delta t]

in this problem:

[(3.1*4.91^2)-(3.1*2.09^2)]/4.91-2.09 = 21.7 m/s

and

[(3.1*2.15^2)-(3.1*2.09^2)]/2.15-2.09 = 13.144 m/s

ya' dig?

i have presumed that by "x=3.1·t2" you mean time squared, or x=3.1·t^2.

the function x=3.1·t^2 defines the particles position at any given time, and average velocity ([delta x]/[delta t]) is the ratio between the change of position and the change in time. word is bond.

Average velocity = displacement/time. That is, (final position - initial position)/time.

"Find the average velocity for the time interval from 2.09 s to 4.91 s"

[x(4.91)-x(2.09)]/(4.91 - 2.09)

"Find the average velocity for the time interval from 2.09 s to 2.15 s."

[x(2.15)-x(2.09)]/(2.15 - 2.09)

Just plug the times into the expression to get the x values.

(a) Plug 'n chug. exchange 2.8 for t and evaluate x (b) Take the a million'st by-product, exchange 2.8 for t and evaluate dx/dt (c) Take the two'nd by-product, exchange 2.8 for t and evaluate d²x/dt² in case you have gotten this a techniques right into a Calculus or Physics class and have not found out a thank you to take derivatives and do undemanding plug 'n chug, you're able to desire to return and initiate over. Doug

1) Vav = [x(4.91) - x(2.09)] / (4.91 - 2.09) and compute

2) Vav = [x(2.15) - x(2.09)] / (2.15 - 2.09) .. compute