A liquid has specific heat of 2.81 J/g•C a mass of 90.0 g and an initial temperature of 25.0 •C what is the new temp of the liquid if?
2,350 J of energy are removed from it?
A. 1.57 •C
B. 9.30 • C
C. 15.7 •C
D. 34.3 •C
E. None of these
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(2350 J) / (2.81 J/g•C) / (90.0 g) = 9.29 °C change
25.0 °C - 9.29 °C = 15.7 °C
So answer C.
q = m c (T2-T1)
-2350 = 90.0 g (2.81 J/gC) (T2-25.0 C)
T2 = 34.3 C