A gas expands, changing its volume by +3.82×10^-4 m^3 while at a constant pressure of 6.63×10^5 Pa. What is the work done by the gas on the surroundings?
What is the work done by the surroundings on the gas?
A gas contracts, changing its volume by -3.82×10^-4 m^3 while at a constant pressure of 6.63×10^5 Pa. What is the work done by the gas on the surroundings?
What is the work done by the surroundings on the gas?
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Verified answer
first:
|w| = p*delta V = (6.63×10^5 Pa)*(3.82×10^-4) = 253,3 J
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second:
first:
w = -p*delta V = -(6.63×10^5 Pa)*(-3.82×10^-4) = 253,3 J