Verified answer

p(t) = (1/2)at^2 + v0 * t + p0

Decompose the velocity vector into horizontal and vertical components (this is the only one we need).

Vy = V * sin(theta)

Vy = 19.0 * sin(36.3)

Now solve for t such that p(t) = 0

0 = (1/2) ( -9.8) * t^2 + Vy * t + 0

find the vertical component of [email protected]°

which will be y if x is horizontal

Vy = 11.25m/s

then time to top of arc from g = delta(v)/t

t = delta(v)/g = -11.25/-9.81 = 1.147s

ane double that to get up + down

2.29s in the air or 2.30 if you round at every step along the way

You need to draw a picture! a triangle with one angle 33 degrees, and make the adjacent side 35. Then, find the cosine of 33 on a calculator and thats your answer.