Verified answer

a) maximum height is when the derivative of f=0

df/dx=-16x+10=0

x=10/16=0.625

f(0.625)=-8*0.625^2+6.25+5

f=8.125ft

b) solve for f(x)=0

x=(-b +/-sqrt(b^2-4ac))/2a (a=-8, b=10, c=5)

x=(-10 +/-sqrt(260))/-16

x=1.633 ft (there is another solution, but that is negative so it requires him to jump backwards)

The x coordinate of the vertex of a parabola equation in the form ax² + bx + c is:

x = -b/2a

In this case, the vertex occurs at x = 5/8. To find the height evaluate the function at x = 5/8:

h = -8(5/8)² + 10(5/8) + 5

To find the when the diver reaches the water set f(x) = 0 and solve for the positive value of x:

0 = -8x² + 10x + 5

0 = 8x² - 10 - 5

Use the quadratic formula

x = {-b + √[b² - 4ac]}/2a

some buddies and that i've got our very own flying licenses, so we take turns flying a helicopter to the incredible of the main suitable snowed mountain, and with exception of the pilot, each and every person else bounce onto the %. of the mountain and snowboarding each and each of ways down... that's merely surprising, and merely like leaping off a diving board, merely like it, yet greater and lots longer.