A charge q of 7.3 × 10^15 coulomb moves from point A to point B in an electric field. If the potential energy?
A charge q of 7.3 × 10^15 coulomb moves from point A to point B in an electric field. If the potential energy of the charge at point A is 3.5 × 10^-12 joules and that at point B is 1.3 × 10^-12 joules, what is the potential difference between point A and B?
A. 1.3 × 10^2 volts
B. 3.0 × 10^2 volts
C. 3.5 × 10^3 volts
D. 6.8 × 10^3 volts
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Your question is flawed. q = 7.3 × 10^15 coulomb is probably Q = 7.3 × 10^-15 C. It is the only way to make the math work.
V = E / Q = ( 3.5 × 10^-12 J - 1.3 × 10^-12 J) / (7.3 × 10^-15 C) = 301V
So the answer is B.
Charge,q=7.3x10^-15 C
Potential energy at A is,VA=3.5x10^-12 J
Potential energy at B is,VB=1.3x10^-12 J
Potential difference between A and B is,V=(VA-VB)/q
=(3.5x10^-12 -1.3x10^-12)/ (7.3x10^-15)
=3.01x10^2 Volt
So,the correct answer is B.