It is easy, just draw the picture out. It will give you a non - right triangle. Then draw in a height from top of the triangle to the bottom of the triangle ( that will make it a right triangle). Then just use sin cos and tan stuff to calculate the velocity and angle. I am sorry i am too lazy to do the whole thing because , i just finished my final exam on physics.
locate the area travelled in both instructions. 93x4.5=418.5 for east, 111x4.5=499.5km for northeast. then draw a scale diagram of this route, and then draw a line linking starting up factor to end. this delivers the displacement. divide that with the help of entire commute time (9h) and also you are able to locate primary speed. Then, use a protractor to degree the attitude of this line you've in simple terms drawn (from north) to locate the route in degrees. wish this solves the priority! :)
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Verified answer
1) (78 x 7.5) + (111 x 7.5) = 1,417.5km. in 15 hrs.
Average = (1417.5/15) = 94.5kph.
(78 x 7.5) = 585km. north.
(111 x 7.5) = 832.5km. after changing direction by 35 degrees right.
North component = (cos 35) x 832.5, = 681.944km.
East component = (sin 35) x 832.5, = 477.5km.
Total north = (585 + 681.944) = 1266.944km.
Total east is 477.5km.
2a) Average velocity = sqrt. (477.5^2 + 1266.944^2) = 1,353.94km.
2b) Direction = arctan (1266.944/477.5) = 69.35 degrees north of east.
It is easy, just draw the picture out. It will give you a non - right triangle. Then draw in a height from top of the triangle to the bottom of the triangle ( that will make it a right triangle). Then just use sin cos and tan stuff to calculate the velocity and angle. I am sorry i am too lazy to do the whole thing because , i just finished my final exam on physics.
locate the area travelled in both instructions. 93x4.5=418.5 for east, 111x4.5=499.5km for northeast. then draw a scale diagram of this route, and then draw a line linking starting up factor to end. this delivers the displacement. divide that with the help of entire commute time (9h) and also you are able to locate primary speed. Then, use a protractor to degree the attitude of this line you've in simple terms drawn (from north) to locate the route in degrees. wish this solves the priority! :)