A car is parked on a cliff overlooking the ocean on an incline that makes an angle of 19.0° below the horizontal. The negligent driver leaves the car in neutral, and the emergency brakes are defective. The car rolls from rest down the incline with a constant acceleration of 3.06 m/s2 for a distance of 60.0 m to the edge of the cliff. The cliff is 20.0 m above the ocean.
(a) Find the car's position relative to the base of the cliff when the car lands in the ocean, and
m
(b) Find the length of time the car is in the air.
s
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Verified answer
Its velocity when it reaches the edge of the cliff is
v = √ 2 as = √ (2*3.06*60) = 19.16
Its vertical velocity at this instant is 19.16 sin 19 and horizontal velocity is
19.16 cos 19.
Time to fall through 20 m is given by
s = ½ gt^2
20 = 4.9 t^2 => t =2.02 s
In this time it travels a horizontal distance of 19.16 cos 19*2.02 = 36.6 m
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b time = 2.02s