A bicycle tire is filled with air to a pressure of 79 psi, at a temperature of 28°C. Riding the bike on asphalt on a hot day increases the temperature of the tire to 58°C. The volume of the tire increases by 3.9%. What is the new pressure in the bicycle tire?
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Generally air pressure changes 1 psi/ 5 degrees C
Use this as a test, for solving with PV=nRT where (d)temp is degrees Kelvin.
I have your details.
As per above: PV = nRT
79psi × (58C+273C)/28C+273C) = 86.87psi
86.87 × (100-3.9)/100 = 83.49 psi
unique PV over T = new PV over T Temp is Kelvin levels that's Celsius plus 273 ninety 9 psi situations l00% quantity over 292 ok = P situations l02.2% over 331 Kelvin temp set this up on paper and pass multiply and sparkling up for the recent P I have been given 109.8 psi