A 55.95 g sample of a substance is initially at 20.1 °C. After absorbing 2101 J of heat, the temperature of t?
A 55.95 g sample of a substance is initially at 20.1 °C. After absorbing 2101 J of heat, the temperature of the substance is 193.8 °C. What is the specific heat (c) of the substance?
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(2101 J) / (55.95 g) / (193.8 - 20.1)°C = 0.2162 J/g·°C