Verified answer

Frictional force F = μ.mg .. .. F = (0.2 x 20 x 9.80) .. .. F = 39.20 N

Resultant force on block = (40.0 - 39.20) = 0.80 N

a = res.force / mass = 0.80N / 20.0kg .. a = 0.040m/s² .. .. ►a = 0.0 m/s² .. (to nearest 0.10)

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