A 2.87×103 kg car rounds a circular turn of?
A 2.87×103 kg car rounds a circular turn of
radius 14.3 m.
The acceleration of gravity is 9.81 m/s2 .
If the road is flat and the coefficient of static
friction between the tires and the road is 0.57,
how fast can the car go without skidding?
Answer in units of m/s
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Verified answer
Maximum centripetal acceleration a = µ*g = 5.59 m/s²
a = V²/R → V = √[a*R] = √[5.59*14.3]
Vmax = 8.94 m/s
The mass doesn't matter.........
F(friction) = F(centrifugal)
=>µmg = mv^2/r
=>v^2 = µrg
=>v = â[0.57 x 14.3 x 9.81]
=>v = 8.94 m/s