After absorbing 1799 J of heat, the temperature of the substance is 197.9 °C. What is the specific heat (c) of the substance?
(1799 J) / (26.20 g) / (197.9 °C - 28.8 °C) = 0.4061 J/g·°C
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(1799 J) / (26.20 g) / (197.9 °C - 28.8 °C) = 0.4061 J/g·°C