A 20g mixture containing 95% (by weight) of A and 5% of B is recrystallized in toluene (b.p. 110°C)?
A 20g mixture containing 95% (by weight) of A and 5% of B is recrystallized in toluene (b.p. 110°C). Solubilities in g/100mL are given below. What amount of solvent is needed to obtain pure A and how much pure A will be recovered? Please show calculations and explain the answers.
Solubility A (g/100 mL) @20°C=1.5g, @100°C=10.0g
Solubility B (g/100 mL) @20°C=0.5g, @100°C=8.0g
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Verified answer
0.95 x 20g = 19g A
1g B
to obtain 19g A, one requires a final concentration of 1.5g/100ml toluene at 20ºC
if you only have 100ml toluene at 20ºC, then you will only recover 1.5g A and 0.5g B, 75% purity
at 100ºC
with only 100ml toluene, you will recover 10g A and 1g B. purity of A = 91%
Bp Toluene