Verified answer

A 16.0 kg box is released on a 35.0° incline and accelerates down the incline at 0.273 m/s2.?

Find the friction force impeding its motion.

Force parallel = mass * 9.8 * sin 35.0°

The force parallel causes the box to accelerate as it moves down the 35.0° incline.

The friction force causes the box to decelerate as it moves down the 35.0° incline.

Net force = force parallel – friction = mass * acceleration

16.0 * 9.8 * sin 35.0° – friction force = 16.0 * 0.273

Friction Force = 16.0 * 9.8 * sin 35.0° – 16.0 * 0.273

Friction Force = 895 N