A 1.57-L flask is filled with propane gas (C3H8), at 1.00 atm and -12.8°C. What is the mass of the propane in the flask?
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How in the heck do you do this???
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n = PV / RT = (1.00 atm) x (1.57 L) / ((0.08205746 L atm/K mol) x (-12.8 + 273) K) = 0.07353 mol C3H8
(0.07353 mol C3H8) x (44.0956 g C3H8/mol) = 3.24 g C3H8