A 1.34×10 3 kg car accelerates uniformly from rest to 12.9 m/s in 2.30 s. a) What is the work done on the car?
Part 1
A 1.34e3kg car accelerates uniformly from
rest to 12.9 m/s in 2.30 s.
a) What is the work done on the car in this
time interval?
Answer in units of J
Part 2
b) What is the power delivered by the engine
in this time interval?
Answer in units of W
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Verified answer
Work done = kinetic energy gained by the object
=0.5 mV^2 = 0.5* 1.34e3*12.9*12.9 = 111494.7 J
2
Power = work / time = 111494.7 / 2.3 = 48476 W
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