The 55-N force acts at 0°. What is the magnitude and direction of the resultant force?
a) ? N (magnitude)
b) ? degrees (direction)
a) resultant force = sqrt[130^2+55^2]=141.2N
b) if we think of the 55N force as lying along the x axis and the 130N force as lying along the y axis, we find the direction of the force from
tan(theta)=y component/x component=130/55
theta=arctan(2.36) =67.1 degrees up from the +x axis
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a) resultant force = sqrt[130^2+55^2]=141.2N
b) if we think of the 55N force as lying along the x axis and the 130N force as lying along the y axis, we find the direction of the force from
tan(theta)=y component/x component=130/55
theta=arctan(2.36) =67.1 degrees up from the +x axis