dy/dx = 3x² - 3

slope at (2,4) = 3·2²-3 = 9

tangent line:

y-4 = 9(x-2)

y = x³ − 3x + 2

Let's find the derivative

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y' = 3x² − 3

Let's find the slope

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m = 3 * 2² - 3

m = 12 - 3

m = 9

Let's find n

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y = mx + n

4 = 9 * 2 + n

n = -14

So the equation of the tangent line is

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y = 9x - 14

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