A 0.500 kg mass of unknown metal at 100.0 •C is placed in 120.0 g H2O at 25.0 •C the final temp of the water and metal is 30.0 •C?
Ignoring the container what is the specific heat of the metal (c-water= 4.184 J/g•C
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Heat gained by water = m c (T2-T1)
qH2O = 120 g (4.184 J/gC) (30-25) = 2510 J
Heat lost by metal = -2510 J = 500 g (c)(30-100C)
c = 0.0717 J/gC