9.If the final temperature of the mixture is 42.5 ∘C,what is the specific heat of the alloy?(Ignore the calorimeter stirrer and thermometer.?
To determine the specific heat of a new metal alloy, 0.180 kg of the substance is heated to 440 ∘C and then placed in a 0.150-kg aluminum calorimeter cup containing 0.430 kg of water at 18 ∘C.
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specific heat of water is 4.186 kJ/kgC = 4.186 J/gC
specific heat Aluminum is 921 J/kgC = 0.921 J/gC
energy gained by water = 430 g x 4.186 J/gC x (42.5–18) = 44099.51 J
energy gained by Al = 150 g x 0.921 J/gC x (42.5–18) = 3384.675 J
energy lost by unknown = 180 g x SH x (440–42.5) = 71550•SH
71550•SH = 44099.51 + 3384.68 = 47484.19
SH = 0.664 J/gC