4x - 4 ≥ -3x^2
find the solution set
write in interval notation
3x^2 + 4x - 4 ≥ 0
(x + 2)(3x - 2) ≥ 0
x ≤ -2 or x ≥ 2/3
(-∞ , -2] U [2/3 , ∞)
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Verified answer
4x - 4 ≥ -3x^2
3x^2 + 4x - 4 ≥ 0
(x + 2)(3x - 2) ≥ 0
x ≤ -2 or x ≥ 2/3
(-∞ , -2] U [2/3 , ∞)