resolve
3x²-17x=-8
3x² - 17x + 8 = 0
3x² - 12x - 2x + 8 = 0
3x(x - 4) - 2(x-4)
(3x - 2)(x-4) = 0
Either 3x - 2 = 0
or x - 4 = 0
Put 3x - 2 = 0
3x = 2
x = 2/3
Put x - 4 = 0
x = 4
So x can be 4 or 2/3
The equation has two solutions
first, you have to bring the -8 to the LHS of the equation, so the equation is:
3x²-17x +8 = 0
then you apply the quadratic formula, where a = 3, b = -17, c = 8
once you get your answer you can simplify it further..but that depends on whether you've learnt complex numbers or not.
First put it in the standard form for a quadratic equation
3x²-17x+8 = 0
There is no nice factorization. You must use the quadratic formula:
x = [-b +/- sqrt(b² - 4ac) ] / 2a
for
ax² + bx + c = 0.
3x²-17x=-8
=>3x²-17x+8=0
solving using general formula:
=>x=[17(+-)sqrt(289-96)]/6
=>x=[17(+-)sqrt(193)]/6
3x² -17x +8 =0
x1=(17+â194)/6
x2=(17-â194)/6
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Verified answer
3x²-17x=-8
3x² - 17x + 8 = 0
3x² - 12x - 2x + 8 = 0
3x(x - 4) - 2(x-4)
(3x - 2)(x-4) = 0
Either 3x - 2 = 0
or x - 4 = 0
Put 3x - 2 = 0
3x = 2
x = 2/3
Put x - 4 = 0
x = 4
So x can be 4 or 2/3
The equation has two solutions
first, you have to bring the -8 to the LHS of the equation, so the equation is:
3x²-17x +8 = 0
then you apply the quadratic formula, where a = 3, b = -17, c = 8
once you get your answer you can simplify it further..but that depends on whether you've learnt complex numbers or not.
First put it in the standard form for a quadratic equation
3x²-17x+8 = 0
There is no nice factorization. You must use the quadratic formula:
x = [-b +/- sqrt(b² - 4ac) ] / 2a
for
ax² + bx + c = 0.
3x²-17x=-8
=>3x²-17x+8=0
solving using general formula:
=>x=[17(+-)sqrt(289-96)]/6
=>x=[17(+-)sqrt(193)]/6
3x² -17x +8 =0
x1=(17+â194)/6
x2=(17-â194)/6