1.5 liters of nitrogen gas is at a pressure of 300 torr. What will the volume be if you reduce the pressure to 110 torr?
1. Charles law - make sure you make temperature into Kelvin
2. Pressure law - no need for any change here but you volume will be in L
So:
1. V1/T1 = V2/T2
0.30 mL / 298 K = V2/353 K
V2 = 0.355 mL
2. P1V1 = P2V2
(300 torr)(1.5 L) = (110 torr)V2
V2 = 4.09 L
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Answers & Comments
1. Charles law - make sure you make temperature into Kelvin
2. Pressure law - no need for any change here but you volume will be in L
So:
1. V1/T1 = V2/T2
0.30 mL / 298 K = V2/353 K
V2 = 0.355 mL
2. P1V1 = P2V2
(300 torr)(1.5 L) = (110 torr)V2
V2 = 4.09 L