2F = 4F – 3/M transpose to give F?
R=2Rn/n+1 ---> in this question also, this is what was done:
r = 2Rn/(n+1)
(n+1)/n = 2R/r
1 + 1/n = 2R/r
1/n = (2R - r)/r <------- Can you please explain how it became 2R - r?
n = r/(2R-r)
Thanks in advance.
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beacuse when you move 1 in this stip
1 + 1/n
in the right side it will become r/r
like this
1/n = ( 2R/ r ) - ( r/r )
1/n = (2R - r ) / r