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what you have there is 2 times the square root of seven, times the square root of 7 again

or 2 * √7 * √7

because multiplication is commutative, lets rewrite this with the 2 at the end

√7 * √7 * 2

now we multiply in order

√7 is defined as the number such that the number multiplied by itself is 7. that's exactly what we're doing; we're multiplying √7 by itself. thus, the product is 7.

now we're left with 7 * 2

I'm not sure where you got 14√7, that's so strikingly wrong :P

if you explain how you got that, someone could explain why that method is wrong, but i can't figure out your method.

b/c √7 *√7 =7 then u multiply by 2 which then = 14

You would combine √7 and√7 to get 2*√7 squared.√7 squared=7. 7*2=14

2√7 * √7

Think about the definition of square root-

The square root of a number, times itself, gives that number.

√4 * √4 is 4

√9 * √9 is 9

√7 * √7 is 7

so

2√7 * √7 is 2 * 7 or 14

ok, 2√7 x √7 will equal:

2(√7)^2 ; distribute the power of 2 & it will cancel with the square root leaving you with:

2(7) which equals 14.

Whats the square root of seven squared? Seven. that's right. The rest is just simple arithmetic 2*7= 14

you multiply the "root 7" and the "root 7" together to get 7. Then you multiply this answer by 2 to get 14.

The Sqrt of number1 will yield a number that when it is multiplied by itself will equal number 1... Sqrt4 = 2 and 2*2 =4

So, when multiplying the Sqrts of the same number, the answer will be the number under the Sqrt.

Sqrt5 * Sqrt5 = 5

Sqrt6 * Sqrt6 = 6

So, Sqrt(n) * Sqrt(n) = n

And in your question you have a magnitude of 2 as well. So,

x(Sqrt(n) * Sqrt(n)) = x(n)

2(Sqrt7 * Sqrt7) = 2(7)

=14

2√7×√7

= 2×(√7×√7)

= 2×7

= 14