Verified answer

divide each term by 5t

so (20t3)/5t= 4t2... so doing this for every term you get:

4t2 - 3t + 6

You have to factor out the numerator...(20t^3-15t^2+30t)

It would be 5t (4t^2-3t+6) all over 5t....the 5t cancels out and you are left with (4t^2-3t+6).

That is the simplest form.

I assue t, t2, t3 are indempendant variables

therefore

(20t3 − 15t2 + 30t) ÷ (5t)

Is

(20t3 − 15t2 + 30t)

------------------------------ = 20t3/5t - 15t2/5t + 30t/5t = 4t3/t-3t2/t + 6

5t

Set it up just like regular long division

... 4t^2 - 3t_+ 6__________

5t)20t^3 - 15t^2 + 30t

....20t^3____________

.............-15t^2

............ -15t^2______

.......................+ 30t

.