4:3 lol. Just so you know for future reference the numbers in front of the respective atoms/compounds usually represent the number of atoms to try and balance the equation. But in this context it is also a ratio and it is also the number of moles. An example would be this:
Mg+02 --> MgO - so one mole of Mg gives one mole of MgO. As you can see there are no numbers in front therefore it represents 1 mole.
Say you had 0.144 moles of Mg how many moles of MgO would be produced?
Using that concept (1 mol of Mg gives 1 mol of MgO)
0.144 mols would therefore be produced.
0.144 mol of Mg gives 0.144 mol of MgO.
If it was like your reaction it would go like this:
2moles of 2Al2O3 gives 4 moles of Al or 3 moles of 02
Anyway hope this helps it took me ages to get the hang of just that lol.
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Verified answer
the answer is d)4:3
the mole ratio of Al to O2 is 4:3 (the coefficients i.e. numbers preceding the elements)
hope this helps:-)
4:3
4:3 lol. Just so you know for future reference the numbers in front of the respective atoms/compounds usually represent the number of atoms to try and balance the equation. But in this context it is also a ratio and it is also the number of moles. An example would be this:
Mg+02 --> MgO - so one mole of Mg gives one mole of MgO. As you can see there are no numbers in front therefore it represents 1 mole.
Say you had 0.144 moles of Mg how many moles of MgO would be produced?
Using that concept (1 mol of Mg gives 1 mol of MgO)
0.144 mols would therefore be produced.
0.144 mol of Mg gives 0.144 mol of MgO.
If it was like your reaction it would go like this:
2moles of 2Al2O3 gives 4 moles of Al or 3 moles of 02
Anyway hope this helps it took me ages to get the hang of just that lol.
the number at the begining is the moles so
d) 4:3