18.0 Ω, 9.00 Ω, and 3.00 Ω resistors are connected in series with an emf source. The current in the 9.00 Ω res?
18.0 Ω, 9.00 Ω, and 3.00 Ω resistors are connected in series with an emf source. The
current in the 9.00 Ω resistor is measured to
be 5.40 A.
a) Calculate the equivalent resistance of the
three resistors in the circuit.
Answer in units of Ω
b) Find the potential difference across the emf
source
Answer in units of V
c) Find the current in the other resistors.
Answer in units of A
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Answers & Comments
Verified answer
a) Resistors in series can be added to get the total resistance. so
18+9+3 = 30 ohms.
b) Using Ohm's Law, E = I R, you get 5.4 x 30 = 16.2 volts.
c) For resistors in series, the same current flows through each of them, so
5.4A.
OK?
Assuming each and all the factors are in sequence the impedance is Z=R+jwL-j/(wC) and the present is V/Z. The voltages are IR, jwLI and -jI/(wC). the skill in the resistor is |I|^2R. you're able to do the mathematics. be unsleeping that Z and that i are complicated numbers.