I know that the 15 has to get out of the ʃ, but from there I get stuck.
ʃ (15e^(7x) / (e^(7x)+1)) dx
Let u = e^(7x)+1
du = 7*e^(7x) dx
15 e^(7x) dx = (15/7) du
ʃ ((15/7) / u ) du =
(15/7)* ln u + C =
(15/7) ln [e^(7x)+1] + C
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ʃ (15e^(7x) / (e^(7x)+1)) dx
Let u = e^(7x)+1
du = 7*e^(7x) dx
15 e^(7x) dx = (15/7) du
ʃ ((15/7) / u ) du =
(15/7)* ln u + C =
(15/7) ln [e^(7x)+1] + C