Verified answer

1.3 and 1.3

The 1.3 moles of HCl is the limiting reagent. With the molar ratio at 1:1, NaCl and H2O are both 1.3 moles.

HCl + NaOH -> NaCl + H2O

Take note of how all the reactants and products are at a 1:1 ratio.

Hence the limiting reagant here would simply be HCl since there is less of it that NaOH.

We use the amount of NaOH to work out moles of NaCl. Since it is at a 1:1 ratio according to the equation

Therefore 1.3 mol of NaCl produced and also 1.3 mol of H2O formed.

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1. Given:

HCl + NaOH → NaCl + H₂O

mol of HCl = 1.3 mol

mol of NaOH = 2.6 mol

Asked:

mol of NaCl formed

mol of H₂O formed

Answer:

Since HCl has the lower mol, HCl becomes the limiting reactant

mol of NaCl formed

= 1/1 x mol of HCl

= 1/1 x 1.3 mol

= 1.3 mol

mol of H₂O formed

= 1/1 x mol of HCl

= 1/1 x 1.3 mol

= 1.3 mol

Reaction: HCl + NaOH → NaCl + H₂O

Initial: 1.3 mol \ 2.6 mol

Reacted: 1.3 mol \ 1.3 mol \ 1.3 mol \ 1.3 mol

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End: ----------- mol \ 1.3 mol \1.3 mol \ 1.3 mol