Verified answer

I think you mean

2√3 / (√3 - 1) and not (2√3 / √3) - 1 which is 2 - 1 = 1

now we need to rationalize denominator

2√3 / (√3 - 1) = 2√3 ( (√3 + 1) / ((√3 - 1) (√3 + 1))

= 2√3 ( (√3 + 1) / (3 - 1)

= 2√3 ( (√3 + 1)/ 2

= √3 ( (√3 + 1)

so shall we divide with the help of two, i dislike that 2x^2 so x^2+4x+5/2 = 0 all of us understand that (x+a)^2 = x^2+2ax+a^2, that's in a similar sort, so if we enable a = 2 (2ax = 4x) it would be extremely comparable (x+2)^2 = x^2+4x+4, that's in basic terms too intense, 3/2 too intense, if we take it off lower back, it's going to be a similar so x^2+4x+5/2 = (x+2)^2-3/2 = 0, (x+2)^2 = 3/2, x+2 = +-rt(3/2) x = -2+-rt(3/2) xd