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您好，我是 lop，高興能解答您的問題。

4[(6-x)/6]

= 4(6-x)/6

= [4(6-x)]/6

= [4(6)-4x]/6

= (24-4x)/6

= [2(12)-2(2x)]/6

= 2(12-2x)/2(3)註(1)

= (12-2x)/3

= 12/3 - 2x/3

= 4 - 2x/3

註：

(1) 約分，分子分母約掉 2

001,

4[(6 - x)/6]

= 4(6/6 - x/6)

= 4[1- (x)/6]

= 4 - (4x)/6

= (12 - 8x)/12

應該係錯的,係呢一行:

= 4 - (4x)/6

再計落去,應該係

(24/6)-(4x6)

=4(6-x)/6

=2(6-x)/3

=(12-2x)/3

4[(6-x)/6]

=(2*2)[(6-x)/(2*3)]

=2[(6-x)/3]

=2(6-x)/3

=(12-2x)/3

4[(6 - x)/6]

= 4[6/6 - x/6]

= 4[1 - x/6]

= 4*1 - 4*x/6

= 4 - 4x/6

= 4 - 2x/3

4[(6 - x)/6]

= 4(6/6 - x/6)

= 4[1- (x)/6]

= 4 - (4x)/6

= (12 - 8x)/12

Hope I can help you.