ʃ 1/x(lnx)^4(dx) Please Check my work?

u=(lnx)^4 du/4=1/xdx 1/4 ʃ1/u(du)= 1/4ln(u)+c= ln(lnx)^4+c

I am not sure if this is right please let me know if I have made mistakes. Thanks.

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