u=(lnx)^4 du/4=1/xdx 1/4 ʃ1/u(du)= 1/4ln(u)+c= ln(lnx)^4+c
I am not sure if this is right please let me know if I have made mistakes. Thanks.
u=ln(x), du=1/x dx
ʃ 1/x ln(x)^4 dx
ʃ u^4 du
1/5 u^5 + C
1/5 ln(x)^5 + C
You have made a mistake. instead let u=Inx, so that du=1/x dx
No integral sign on my keyboard,
Replace 1/x dx with du then the expression becomes
integral of u^4 du
= 1/5 u^5 + C
since u = Inx
= (1/5)(Inx)^5 + C
http://www.wolframalpha.com/input/?i=%CA%83+1%2Fx%...
Or
http://www.wolframalpha.com/input/?i=%CA%83+1%2F%2...
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Verified answer
u=ln(x), du=1/x dx
ʃ 1/x ln(x)^4 dx
ʃ u^4 du
1/5 u^5 + C
1/5 ln(x)^5 + C
You have made a mistake. instead let u=Inx, so that du=1/x dx
No integral sign on my keyboard,
Replace 1/x dx with du then the expression becomes
integral of u^4 du
= 1/5 u^5 + C
since u = Inx
= (1/5)(Inx)^5 + C
http://www.wolframalpha.com/input/?i=%CA%83+1%2Fx%...
Or
http://www.wolframalpha.com/input/?i=%CA%83+1%2F%2...