You remove two socks from a hot dryer and find that they repel with force of 0.003 N when they’re 3 cm apart.?
You remove two socks from a hot dryer and find that they repel with force of 0.003 N when they’re 3 cm apart. If they have equal charges, and you separate the socks until they’re 7 cm apart, what force will each sock exert on the other? Round the answer to 3 significant digits.
Please show me how to calculate this.
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The force of repulsion F = k [q/r]^2 if q's are equal.
F1 = k q^2 / r1^2 -------------1
F2 = k q^2 / r2^2--------------2
Therefore,
F1/F2 =[ r2/r1] ^2 or F2 = F1* [ r1/r2]^2
F2 = 0.003 * [3/ 7]^2 We need not change to meter since
r1/r2 is only a ratio.
F2 =0.000551 N
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