This is the equation of a circle with centre at the origin(0,0) and of radius 5 units.
So, x and y may assume any value such that (x,y) lies on the circumfirence of the circle.
For exact solution, another equation is necessary.
x= 4 and y= 3 cuz 3 squared is 9 and 4 squared is 16 and 16+9=25
for x:
x^2+y^2=25
-y^2 both sides
x^2=25-y^2
square root (sqrt) both sides
x=Sqrt(25-y^2
x=5-y
for y:
-x^2 both sides
y^2=25-x^2
sqrt both sides
y=sqrt(25-x^2
y=5-x
Hope this helps!
x^2 -25=-y^2
x-5=y
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Verified answer
This is the equation of a circle with centre at the origin(0,0) and of radius 5 units.
So, x and y may assume any value such that (x,y) lies on the circumfirence of the circle.
For exact solution, another equation is necessary.
x= 4 and y= 3 cuz 3 squared is 9 and 4 squared is 16 and 16+9=25
for x:
x^2+y^2=25
-y^2 both sides
x^2=25-y^2
square root (sqrt) both sides
x=Sqrt(25-y^2
x=5-y
for y:
-x^2 both sides
y^2=25-x^2
sqrt both sides
y=sqrt(25-x^2
y=5-x
Hope this helps!
x^2 -25=-y^2
x-5=y