y3 is actually y to the cube and then the 16 x to the cube and on the last its x to the cube not x3
Evaluate the radicands and combine like radicand if necessary...
5xy√(2y) - y * 2x∛(2y) - y * 2x√(2y) - x³ * 3y²√(6)
= 5xy√(2y) - 2xy∛(2y) - 2xy√(2y) - 3x³y²√(6)
Nothing to combine like radicands due to unlike radicands.
Good luck!
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Verified answer
Evaluate the radicands and combine like radicand if necessary...
5xy√(2y) - y * 2x∛(2y) - y * 2x√(2y) - x³ * 3y²√(6)
= 5xy√(2y) - 2xy∛(2y) - 2xy√(2y) - 3x³y²√(6)
Nothing to combine like radicands due to unlike radicands.
Good luck!