Verified answer

(2, 4) and parallel to y = 4x + 8

point slope form

y = mx + b

where m = slope and b = y-intercept

parallel lines have the same slope

y = 4x + 8 has a slope, m = 4 <====

use this slope value in the new equation

using the given point, solve for the y-intercept, b

4 = 4(2) + b

4 = 8 + b

subtract 8 from both sides of the equation to isolate b

4 - 8 = b

-4 = b <==== y-intercept

with m = 4 and b = -4

y = 4x - 4 <==== slope-intercept form

y=4x-4

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