You could use the following formula
sin(A-B) = (sinA)(cosB) - (cosA)(sinB)
Let x = theta
sin(pi/2 - x) = (sin(pi/2))cosx - (cos(pi/2))(sinx)
= (1)(cosx) - (0)(sinx) = cos x
Now, cosine is an odd function meaning cosx = cos(-x).
sin(A+B)=sinAcosB+cosAsinB
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Verified answer
You could use the following formula
sin(A-B) = (sinA)(cosB) - (cosA)(sinB)
Let x = theta
sin(pi/2 - x) = (sin(pi/2))cosx - (cos(pi/2))(sinx)
= (1)(cosx) - (0)(sinx) = cos x
Now, cosine is an odd function meaning cosx = cos(-x).
sin(A+B)=sinAcosB+cosAsinB